Step 10 of 10
Challenge: squeeze out spaces
Another two-pointer classic: a read pointer scans every character, while a write pointer only advances when a character is kept. Everything happens in the same buffer, no extra memory.
"a b c" read -> a _ b _ _ c
"abc" write -> a b c \0
Don't forget to write the '\0' terminator at the final write position.
Your turn: write void squeeze(char *s) that removes every space from s in place.