Step 1 of 6

std::map

A vector finds things by position: element 0, element 1, and so on. Often you want to find things by a name instead: the score for "ropz", the price of "awp", the phone number for "Ada". That's what a map is for. std::map<Key, Value> stores key/value pairs, keeps them sorted by key, and never holds the same key twice.

#include <iostream>
#include <map>
#include <string>

int main() {
    std::map<std::string, int> stock;
    stock["apple"] = 5;
    stock["pear"] = 2;
    stock["apple"] += 3;        // the key exists, so this updates it
    stock["kiwi"]++;            // the key is new, so it starts at 0, then becomes 1
    std::cout << stock.size() << " kinds\n";
    for (const auto& [fruit, n] : stock) {
        std::cout << fruit << ": " << n << "\n";
    }
}

3 kinds
apple: 8
kiwi: 1
pear: 2

How it works

• m[key] gives you a reference to the value for key. If the key isn't there yet, [] first inserts it with a default value: 0 for numbers, "" for strings. That's why stock["kiwi"]++ works on a brand new key.
• Looping over a map visits the entries in key order (alphabetical for strings, ascending for numbers), no matter what order you inserted them in.
• Each entry is a std::pair<const Key, Value>. const auto& [fruit, n] is a structured binding: it unpacks the pair into two named variables. Without it you'd write entry.first and entry.second.
• A map is a balanced binary search tree inside, so insert and lookup take O(log n) steps.

The counting pattern

"How many times does each thing appear?" is one of the most common jobs in programming, and a map makes it one line: count[thing]++. Missing keys start at 0 automatically.

Common mistakes

• Writing for (auto [k, v] : m) copies every entry. Use const auto& to read without copying.
• Forgetting that a map keeps only one value per key. Assigning to an existing key replaces the old value.

Your task

Count how many times each word appears in the input and print word count lines in alphabetical order.

Challenge 2

The input is name kills pairs from several rounds. Add up each player's kills with a std::map and print name total lines in alphabetical order. Input ropz 3 rain 1 ropz 4 prints rain 1 and ropz 7.

Challenge 3

Count the words in the input, then print word count lines sorted by count, most first, with ties in alphabetical order. A map sorts by key only, so copy its entries into a vector and sort that.

Next: Look up without inserting